[ale] Anyone familiar with R?
Ed Cashin
ecashin at noserose.net
Tue Apr 5 13:38:37 EDT 2011
To answer your original question, I like and use R. I didn't want
crickets to be the only response. :)
On Tue, Apr 5, 2011 at 11:04 AM, George Allen <glallen01 at gmail.com> wrote:
> ...and figured out my other error after another cup of coffee...
> I was using an or instead of and, x > a | x < b should have been x > a & x < b,
> so of course it selected everything. Just wasn't thinking straight.
>
> On Tue, Apr 5, 2011 at 9:24 AM, George Allen <glallen01 at gmail.com> wrote:
>> Nevermind, typo fixed it. Doh!
>>
>> s/2010/2011/g
>>
>>
>> On Tue, Apr 5, 2011 at 9:23 AM, George Allen <glallen01 at gmail.com> wrote:
>>> I'm trying to learn R, as well as analyze some data out of Cisco
>>> Unified Contact Center (call center setup) for a helpdesk. UCCX has an
>>> app that will generate reports via crystal reports into excel, but
>>> it's cumbersome and doesn't exactly generate what I want.
>>>
>>> So...
>>>
>>> Have a data set like:
>>>
>>>> head(z)
>>> r$SESSION.ID START_DATETIME QUEUE.TIME TALK.TIME HOLD.TIME WORK.TIME
>>> 1 1-5000003350-0 2011-03-01 07:00:03 297 134 0 4
>>> 2 1-5000003351-0 2011-03-01 07:02:23 234 404 0 30
>>> 3 1-5000003353-0 2011-03-01 07:05:33 120 214 0 30
>>> 4 1-5000003356-0 2011-03-01 07:09:32 137 229 0 30
>>> 5 1-5000003358-0 2011-03-01 07:12:49 69 577 0 30
>>> 6 1-5000003360-0 2011-03-01 07:21:38 29 288 0 30
>>>
>>> and I want to do something like:
>>>
>>> subset(z, z$START_DATETIME >= as.POSIXlt('2010-03-01') |
>>> z$START_DATETIME <= as.POSIXlt('2010-03-07'), "START_DATETIME")
>>>
>>> to pull one week's worth of data, but instead it dumps the whole dataframe.
>>> Ultimately, I want to do this:
>>>
>>> hist(z[z$START_DATETIME >= as.POSIXct('2010-03-01') | z$START_DATETIME
>>> <= as.POSIXct('2010-03-07'), "START_DATETIME"], 'hours', freq=TRUE)
>>>
>>> and have it dump only that first week, currently it does the whole set...
>>>
>>
>
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--
Ed Cashin <ecashin at noserose.net>
http://noserose.net/e/
http://www.coraid.com/
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