[ale] Perl question

[Fletch]

>>>>> "Matthew" == Matthew Brown <matthew.brown at cordata.net> writes:

[...]

    Matthew> The command I am running follows:
 
    Matthew> $ find . -name "*.php" -maxdepth 3 | perl -p -i.bak -e
    Matthew> "s/foo/bar/;"
 
    Matthew> On my box, this simply tries to change 'foo' to 'bar' in
    Matthew> the file _names_ handed to it.  What am I missing?
 
        xargs before perl.

find  . -name "*.php" -maxdepth 3 | xargs perl -i.bak -pe 's/foo/bar/'

        You're passing it the names of the files on its standard in.
The edit in place `-i -p' magic (or `-i -n' as well) requires the
names of the files to be passed as command line arguments, but you're
not giving it any so it defaults to working on STDIN instead (just as
<> would do in any other case).


-- 
Fletch                | "If you find my answers frightening,       __`'/|
fletch at phydeaux.org   |  Vincent, you should cease askin'          \ o.O'
770 933-0600 x211(w)  |  scary questions." -- Jules                =(___)=
770 294-0820 (m)      |                                               U

---
This message has been sent through the ALE general discussion list.
See http://www.ale.org/mailing-lists.shtml for more info. Problems should be 
sent to listmaster at ale dot org.