[ale] Stumped-

[Scott McBrien]

Dennis,

You're likely going to have problems with the $(ls) to generate the  
stuff for your for loop.  I've had problems with large volume of  
arguments provided with for, so you may need to swich to a while loop  
out of a file of clients.

What I'd try is using find to populate a list of client files, the  
sort them using the last field so that you get the files with the same  
name grouped together.  Then instead of ls, maybe stat would give you  
the size that's easier to grab.

-Scott

On Mar 11, 2010, at 7:31 AM, Dennis Ruzeski <denniruz at gmail.com> wrote:

> The direction  I've been going in is to do something like this-
>
> for dir in `ls /client`
> do diff -s $dir/images $dir/movies |grep ^F |xargs ls -l
> done
>
>
>
> On Thu, Mar 11, 2010 at 10:26 AM, Dennis Ruzeski  
> <denniruz at gmail.com> wrote:
>> Same name but different size.
>>
>>
>>
>> On Thu, Mar 11, 2010 at 10:14 AM, Dave Weiner <davew at coyotetechnical.com 
>> > wrote:
>>> Dennis Ruzeski wrote:
>>>> Exactly- I need to look in images and movies for the same file name
>>>> with different sizes for each client.
>>>
>>> So you need to loop through all the files in the images dir for  
>>> client1
>>> and check for files with the same name in the other 9,999 image  
>>> directories?
>>>
>>>>
>>>> --Dennis
>>>
>>> Dave
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>>
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