[ale] Silly bash question

[Don Lachlan]

On Thu, Nov 12, 2009 at 3:51 PM, Ed Cashin <ecashin at noserose.net> wrote:
>  for pid in `jobs -p`; do
>             echo `ps aux | awk -vp=$pid '$2==p{print $11}'`: "$pid"
>  done

If you aren't redirecting stdout, you don't need "echo". And you
actually don't need "awk" if you already know the pid.


for pid in `jobs -p` ; do
  ps -p ${pid} --no-headers -o 'pid,args'
done


>From the 'ps' man page:

-p pidlist      Select by PID.
                       This selects the processes whose process ID
numbers appear in pidlist.
                       Identical to p and --pid.

-o format       user-defined format.
                       format is a single argument in the form of a
blank-separated or
                       comma-separated list, which offers a way to
specify individual output
                       columns. The recognized keywords are described
in the STANDARD FORMAT
                       SPECIFIERS section below.

--no-headers    print no header line at all. --no-heading is an alias
for this option.


Generally, if you're considering 'awk' and 'ps' together, then you
want to use at least one of those three options.

-Lachlan