[ale] Bash (or whatever) question

[fletch at phydeaux.org]

> I have a directory with softlinks to a number of files that no longer
> exist, along with links to files that _do_ exist.
>
> How can I selectively list those links which are _not_ satisfied, so I can
> remove them at one go, while ignoring those for which the linked files
> still exist?

lemur:~/linktest 712> ls -la                                          
23:14:39
total 16
drwxr-xr-x   5 fletch  fletch   170 15 Feb 23:13 ./
drwxr-xr-x  89 fletch  fletch  3026 15 Feb 23:12 ../
lrwxr-xr-x   1 fletch  fletch    10 15 Feb 23:12 bad@ -> /not/there
lrwxr-xr-x   1 fletch  fletch    10 15 Feb 23:12 good@ -> /etc/hosts
-rw-r--r--   1 fletch  fletch     0 15 Feb 23:13 regular_file
lemur:~/linktest 713> perl -le 'for(grep -l, glob("*")){$l=readlink;warn
"broked: $_ => $l\n" unless -e $l}'
broked: bad => /not/there


Or . . .


ruby -le
'Dir.glob("*").select{|f|File.symlink?(f)}.each{|f|l=File.readlink(f);$stderr.print
"broked: #{f} => #{l}" if !File.exist?(l)}'

-- 
Fletch                | "If you find my answers frightening,       __`'/|
fletch at phydeaux.org|  Vincent, you should cease askin'          \ o.O'
                      |  scary questions." -- Jules                =(___)=
                      |                                               U