[ale] Looking for duplicate photos
Jim Patterson
unixdude at gmail.com
Sun Feb 6 11:56:30 EST 2005
Trey,
The following script is primitive, but I think it should work fine for you.
If you name if del_dup.sh, then run it with:
./del_dup.sh /photos /photos/* /photos/*/*
It does not recurse automagicaly, but you can extend it with too much
work. Just take the top level directory and use find to locate all the
sub-directories. Then pass that list to ls. NOTE: you can not use
ls -R since that breaks each directory into seperate sections.
Jim P.
#! /bin/sh
oldsize="-"
oldfile="-"
for f in `ls --sort=size $*`
do
dl=`ls -l "$f" | tr -s " "`
size=`echo $dl | cut -f 5 -d " "`
file=`echo $dl | cut -f 9 -d " "`
if [ "$oldsize" = "$size" ]
then
if diff -q "$oldfile" "$file" >/dev/null
then
echo Deleting $file dup of $oldfile
rm "$file"
fi
else
oldsize=$size
oldfile=$file
fi
done
On Sun, 06 Feb 2005 11:19:42 -0500, Trey Sizemore <trey at fastmail.fm> wrote:
> I've got a number of photos from my digital camera stored on my machine
> and a number of them are duplicates. I was wondering if there was a
> script that would identify the duplicates and their locations so I can
> purge them to better organize and post. There is a /photos directory
> that itself contains both photos and other sub-directories so it would
> need to search both the /photos directory and all sub-directories within
> it.
>
> Am I wishfully thinking? I don't have experience with sed and awk
> (although I've used grep and pipes in the past) but this is beyond my
> limited understanding.
>
> Thanks.
>
> --
> Cheers,
> Trey
> ---
>
> "Men do not differ much about what things they will call evils;
> they differ enormously about what evils they will call excusable."
> -- GK Chesterton
>
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