[ale] Shell Scripting question

[nick travis]

thanks for the help, what can I use to get the last three words off of a
line, instead of just the last word?

On Wed, 2003-08-06 at 13:53, Geoffrey wrote:
> nick travis wrote:
> > Here's the exact line in the file, I want to pull out the file name from
> > it.
> > VIOLATION  : PAM service rlogin (/etc/pam.d/rlogin) does not have module
> > pam_shells.so for module type auth.
> > ...ACTION  : Add module pam_shells.so for module type auth to PAM
> > service rlogin (/etc/pam.d/rlogin).
> > Example: auth     required    /lib/security/pam_shells.so
> > 
> > there will be several violations like this in the file, but the file
> > name will start at a different location each time.  since the violation
> > will be in a different file.
> 
> Well, that message contains three different references to file names, 
> but you can get to all of them with the right tool.  If for example you 
> want the name that's contained between the parans, you can use awk:
> 
> awk -F '[()]' '{print $2}' intputfile
> 
> The above will retreive the first occurance of /etc/pam.d/rlogin. 
> Basically you're telling awk that there are two field separators and 
> they are the parans.  Therefore, the file name would be the second field.
> 
> Same solution would apply for the second /etc/pamd./rlogin entry, you'd 
> just have to adjust the '$2' appropriately.
> 
> The last file reference (/lib/security/pam_shells.so) can be had by the 
> previous posted solution:
> 
> awk '{print $NF}' inputfile
> 
> 
> NF in awk is the number of fields, therefore $NF is the last field value.

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