[ale] C Programming Question
JB Wells
jbwellsiv at yahoo.com
Tue Mar 6 13:50:43 EST 2001
I think this will work:
char **a=(char **)malloc (sizeof(char **));
for (i=0; i<WHATEVER; i++)
{
/* if the pointer will be pointing to a string,
you should change it to
(char *)malloc(sizeof(char) * strlen(STRING))*/
a[i]=(char *)malloc(sizeof(char *));
}
=====
--------------------------
John B. Wells IV
Application Developer
Acterna
6100 Lake Forrest Drive
Atlanta, GA 30328
404.531.8938
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